Grub

[svizi 0]

How can i configure my grub bootloader on a suse 9.0 in order to boot my 2.6.2 kernel ?

[Dapper Dan 0]

You would do it in /grub/grub.conf. In RH it's usually in the /boot directory. I don't know what you have in a SuSe grub.conf or how or where the kernels are listed, but here's my grub.conf which gives several as choices. Maybe it will give you some ideas. Sorry I couldn't help more.

 

Code:

# added by NeTraverse - DO NOT REMOVE THIS LINE, it's used for uninstalldefault 5# end added by NeTraverse - DO NOT REMOVE THIS LINE, it's used for uninstall# grub.conf generated by anaconda## Note that you do not have to rerun grub after making changes to this file# NOTICE:  You have a /boot partition.  This means that#          all kernel and initrd paths are relative to /boot/, eg.#          root (hd0,4)#          kernel /vmlinuz-version ro root=/dev/hda6#          initrd /initrd-version.img#boot=/dev/hdatimeout=10splashimage=(hd0,4)/grub/splash.xpm.gztitle Red Hat Linux (2.4.20-28.1.caps.rh90.ccrma)	root (hd0,4)	kernel /vmlinuz-2.4.20-28.1.caps.rh90.ccrma ro root=LABEL=/ hdc=ide-scsi hdd=ide-scsi	initrd /initrd-2.4.20-28.1.caps.rh90.ccrma.imgtitle Red Hat Linux (2.4.20-27.9)	root (hd0,4)	kernel /vmlinuz-2.4.20-27.9 ro root=LABEL=/ hdc=ide-scsi hdd=ide-scsi	initrd /initrd-2.4.20-27.9.imgtitle Red Hat Linux (2.4.20-20.9)	root (hd0,4)	kernel /vmlinuz-2.4.20-20.9 ro root=LABEL=/ hdc=ide-scsi hdd=ide-scsi	initrd /initrd-2.4.20-20.9.imgtitle Red Hat Linux (2.4.20-8)	root (hd0,4)	kernel /vmlinuz-2.4.20-8 ro root=LABEL=/ hdc=ide-scsi hdd=ide-scsi	initrd /initrd-2.4.20-8.imgtitle DOS	rootnoverify (hd0,8)	chainloader +1# added by NeTraverse - DO NOT REMOVE THIS LINE, it's used for uninstalltitle Win4Lin	root (hd0,4)	kernel /win4lin ro root=LABEL=/ hdc=ide-scsi hdd=ide-scsi	initrd /initrd-2.4.20-8.img# end added by NeTraverse - DO NOT REMOVE THIS LINE, it's used for uninstall